python - Need to remove items from both a list and a dictionary of tuple value pairs at same time -

this related previous question realised objective more complicated:

i have sentence: "forbes asia 200 best under 500 billion 2011"

i have tokens like:

oldtokens = [u'forbes', u'asia', u'200', u'best', u'under', u'500', u'billion', u'2011'] 

and indices of previous parser has figured out there should location or number slots:

numbertokenids =  {(7,): 2011.0, (2,): 200.0, (5,6): 500000000000.00} locationtokenids = {(0, 1): u'forbes asia'} 

the token ids correspond index of tokens there locations or numbers, objective obtain new set of tokens like:

newtokens = [u'asia', u'200', u'best', u'under', u'500', u'2011'] 

with new number , location tokenids perhaps (to avoid index out of bounds exceptions):

numbertokenids =  {(5,): 2011.0, (1,): 200.0, (4,): 500000000000.00} locationtokenids = {(0,): u'forbes asia'} 

essentially go through new reduced set of tokens, , able create new sentence called:

"location_slot number_slot best under number_slot number_slot" 

via going through new set of tokens , replacing correct tokenid either "location_slot" or "number_slot". if did current set of number , location token ids, get:

"location_slot location_slot number_slot best under number_slot number_slot number_slot". 

how this?

another example is:

location token ids are:  (0, 1) number token ids are:  (3, 4) old sampletokens [u'united', u'kingdom', u'usd', u'1.240', u'billion'] 

where want both delete tokens , change location , number token ids able replace sentence like:

sampletokens[numbertokenid] = "number_slot" sampletokens[locationtokenid] = "location_slot" 

such replaced tokens [u'location_slot', u'usd', u'number_slot']

not elegant, working solution:

oldtokens = [u'forbes', u'asia', u'200', u'best', u'under', u'500', u'billion', u'2011']  numbertokenids =  {(7,): 2011.0, (2,): 200.0, (5,6): 500000000000.00} locationtokenids = {(0, 1): u'forbes asia'}  newtokens = [] newnumbertokenids = {} newlocationtokenids = {}  new_ind = 0 skip = false  ind in range(len(oldtokens)):     if skip:         skip=false         continue      loc_ind in locationtokenids.keys():         if ind in loc_ind:             newtokens.append(oldtokens[ind+1])             newlocationtokenids[(new_ind,)] = locationtokenids[loc_ind]             new_ind += 1             if len(loc_ind) > 1: # skip next position if there 2 elements in tuple                 skip = true             break     else:         num_ind in numbertokenids.keys():             if ind in num_ind:                 newtokens.append(oldtokens[ind])                 newnumbertokenids[(new_ind,)] = numbertokenids[num_ind]                 new_ind += 1                 if len(num_ind) > 1:                     skip = true                 break         else:             newtokens.append(oldtokens[ind])             new_ind += 1  newtokens out[37]: [u'asia', u'200', u'best', u'under', u'500', u'2011']  newnumbertokenids out[38]: {(1,): 200.0, (4,): 500000000000.0, (5,): 2011.0}  newlocationtokenids out[39]: {(0,): u'forbes asia'}