javascript - Detecting user desktop inactivity using WebExtensions -

i have add-on , want issue notifications on desktop, if user actively using computer (e.g mouse pointer moving anywhere, i.e, not in browser window).

it possible using webextensions?

i believe this:

• script.js

  function notify(id, title, message) {     var props = {         "type":    "basic",         "title":   title,         "iconurl": "images/icon-128px.png",         "message": message     };      var propscopy = json.parse(json.stringify(props));      propscopy.requireinteraction = true;      //prevent exception in firefox     try {         chrome.notifications.create(id, propscopy, function() {});     } catch (ee) {         chrome.notifications.create(id, props, function() {});     } } 

• background.js

  var standbynotifications = [];  function registernotification(id, title, message) {     if ([user inactive]) {         standbynotifications.push({ "id": id, "title": title, "message": message });     } else {         notify(id, title, message);     } }  setinterval(function() {     if ([user inactive] === false) {         var tmp = standbynotifications.reverse();          (var = tmp.length - 1; >= 0; i--) {             notify(tmp[i].id, tmp[i].title, tmp[i].message);         }          standbynotifications = []; //clear     } }, 1000); 

chrome has dedicated api, chrome.idle, detect idle state.

chrome.idle.querystate(   5 * 60, // seconds   function(state) {     if (state === "active") {       // computer not locked, user active in last 5 minutes     } else {       // computer locked, or user inactive 5 minutes     }   } ); 

it provides event, chrome.idle.onstatechanged, notify when state changes.

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webextensions list api not yet supported (2016-07-21).

• querystate reports "active" state.
• onstatechanged not available.