bash - Read specific information from the "echo" command while printing and ignoring others -

i writing bash scripts , faced following problem. let's say:

function echo_ignore_print() {     echo "ignoring print" # print line user without storing value     value=187fef     echo "$value" # return value }  info_to_keep=$(echo_ignore_print)  echo "$info_to_keep"   #   ignoring print 187fef 

i need able print "ignoring print" script gets line need return value of variable "$value" itself, can use later on. rather not have global variables.

therefore, there way king of dump string of echo command , save later? or other way this?

thank help.

you can write to-be-ignored stuff on stderr instead of stdout:

echo_ignore_print() {    echo "ignoring print" >&2    value='187fef'    echo "$value" }  info_to_keep=$(echo_ignore_print) ignoring print  echo "$info_to_keep" 187fef