how sort group of elements within node of xml file.
here input
<root> <level_1.1>...</level_1.1> <level_1.2>...</level_1.2> <level_1.3> <sub.1>...</sub.1> <sub.2> <s.1>1</s.1> <s.3>something</s.3> <s.6>c</s.6> <s.2/> <s.4> <aa.1>2</aa.1> </s.4> <s.5/> </sub.2> <sub.3>...</sub.3> </level_1.3> <level_1.4>...</level_1.4> </root> would have output same hierarchy location below.
<root> <level_1.1>...</level_1.1> <level_1.2>...</level_1.2> <level_1.3> <sub.2> <s.1>1</s.1> <s.2/> <s.3>something</s.3> <s.4><aa.1>2</aa.1></s.4> <s.5/> <s.6>c</s.6> </sub.2> <sub.3>...</sub.3> </level_1.3> <level_1.4>...</level_1.4> </root> this have tried other's suggestion it's not working.
<xsl:template match="/root/level_1.3"> <xsl:copy> <xsl:apply-templates> <xsl:sort select="sub.2" order="ascending"/> </xsl:apply-templates> </xsl:copy>
try way?
xslt 1.0
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform"> <xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/> <xsl:strip-space elements="*"/> <!-- identity transform --> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <xsl:template match="sub.2"> <xsl:copy> <xsl:apply-templates> <xsl:sort select="name()" data-type="text" order="ascending"/> </xsl:apply-templates> </xsl:copy> </xsl:template> </xsl:stylesheet> 
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