i writing method using python , believe continue statement not working properly. can explain me wrong there?
the method code below:
def xltolinkeddt(lst1, lst2, name1, name2): logging.info(">> new iteration") dates1, times1, dates2, times2 = [], [], [], [] i, (dt1, dt2) in enumerate(zip(lst1, lst2)): if bool(dt1) + bool(dt2) == 1: name = name1 if not dt1 else name2 issues.append("the %s date of trip no. %d must provided." %(name, i+1)) dates1.append("") dates2.append("") times1.append("") times2.append("") logging.info("exiting loop") continue logging.info(continued after bool condition.) raise assertionerror("stop!") when run code error , following logging in 1 of iterations:
>> new iteration >> exiting loop >> continued after bool condition the code not supposed log both messages, 1 of them. when replaced continue break worked well. missing?
the code not supposed log both messages.
yes, is.
after code executes continue, loop moves beginning of block inside for-loop, in next iteration. if condition in if-block not met @ next iteration, behaviour describe.
in [5]: in range(10): print("trying i={:d}".format(i)) if i%2 == 0: print("`i` even, continuing") continue print("what doing here?") ...: trying i=0 `i` even, continuing trying i=1 doing here? trying i=2 `i` even, continuing trying i=3 doing here? trying i=4 `i` even, continuing trying i=5 doing here? trying i=6 `i` even, continuing trying i=7 doing here? trying i=8 `i` even, continuing trying i=9 doing here? as can see, there still what doing here? printed after i even, continuing notification, belongs later iteration of loop. if replace continue break, different behaviour:
in [6]: in range(10): print("trying i={:d}".format(i)) if i%2 == 0: print("`i` even, not continuing") break print("what doing here?") ...: trying i=0 `i` even, not continuing as can see, stops because (by our definition), 0 even.
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