linux - How to achieve two echo statement output to same line in bash -

example: have below test script

#!/bin/bash  output1=$(cat ~/desktop/scripts/test) output2=$(cat ~/desktop/scripts/test2 |sed -e 's/^/\t/g') echo -e "$output1 $output2" 

when execute above script getting below output

1234 5678 9123    ndfkjdskjgbsd         sdnbfksdjgkjdsb         sdnbvksd         dbvksdbgf 

but looking output below, how can achieve?

1234      ndfkjdskjgbsd 5678      sdnbfksdjgkjdsb 9123      sdnbvksd           dbvksdbgf 

use paste:

paste ~/desktop/scripts/test ~/desktop/scripts/test2 

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however, if really want in native shell exercise:

while ifs= read -r line1 <&3; ifs= read -r line2 <&4; [[ $line1 || $line2 ]];     printf '%s\t%s\n' "$line1" "$line2" done 3<~/desktop/script/test 4<~/desktop/script/test2 

this works opening first file on fd 3, second file on fd 4, , working through both files line-by-line until there's no new content available either.