Python 2.7: Returning a value in a csv file from input -

i've got csv with:

t,8,101 t,10,102 t,5,103 

and need search csv file, in 3rd column input, , if found, return 2nd column value in same row (searching "102" return "10"). need save result use in calculation. (i trying print result now..) new python (2 weeks) , wanted grasp on reading/writing in csv files. searchable results, didn't give me answer needed. thanks

here code:

name = input("waiting") import csv open('cards.csv', 'rt') csvfile:     reader = csv.reader(csvfile, delimiter=',')     row in reader:         if row[2] == name:             print(row[1]) 

as stated in comment above implement general approach without using csv-module this:

import io  s = """t,8,101 t,10,102 t,5,103"""  # use io.stringio file-like object f = io.stringio(s) lines = [tuple(line.split(',')) line in f.read().splitlines()]  example_look_up = '101'  def find_element(look_up):     t in lines:         if t[2] == look_up:             return t[1]  result = find_element(example_look_up) print(result) 

please keep in mind, python3-code. need replace print() print if using python2 , maybe change related stringio using demonstration purposes here in order file-like object. however, snippet should give basic idea possible solution.